2x(4-3x)=16

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Solution for 2x(4-3x)=16 equation: 



2x(4-3x)=16

We move all terms to the left:

2x(4-3x)-(16)=0

We add all the numbers together, and all the variables

2x(-3x+4)-16=0

We multiply parentheses

-6x^2+8x-16=0

a = -6; b = 8; c = -16;
Δ = b2-4ac
Δ = 82-4·(-6)·(-16)
Δ = -320
Delta is less than zero, so there is no solution for the equation

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