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2x(4x+-1)=4+2x
We move all terms to the left:
2x(4x+-1)-(4+2x)=0
We add all the numbers together, and all the variables
2x(4x-1)-(2x+4)=0
We multiply parentheses
8x^2-2x-(2x+4)=0
We get rid of parentheses
8x^2-2x-2x-4=0
We add all the numbers together, and all the variables
8x^2-4x-4=0
a = 8; b = -4; c = -4;
Δ = b2-4ac
Δ = -42-4·8·(-4)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-12}{2*8}=\frac{-8}{16} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+12}{2*8}=\frac{16}{16} =1 $
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