2x(4x+25)=0

Solution for 2x(4x+25)=0 equation:

2x(4x+25)=0

We multiply parentheses

8x^2+50x=0

a = 8; b = 50; c = 0;
Δ = b2-4ac
Δ = 502-4·8·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50}{2*8}=\frac{-100}{16}
=-6+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50}{2*8}=\frac{0}{16}
=0
$