2x(4x+28)=180

Solution for 2x(4x+28)=180 equation:

2x(4x+28)=180

We move all terms to the left:

2x(4x+28)-(180)=0

We multiply parentheses

8x^2+56x-180=0

a = 8; b = 56; c = -180;
Δ = b2-4ac
Δ = 562-4·8·(-180)
Δ = 8896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8896}=\sqrt{64*139}=\sqrt{64}*\sqrt{139}=8\sqrt{139}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-8\sqrt{139}}{2*8}=\frac{-56-8\sqrt{139}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+8\sqrt{139}}{2*8}=\frac{-56+8\sqrt{139}}{16}
$