2x(4x+3)=10x-3

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Solution for 2x(4x+3)=10x-3 equation: 



2x(4x+3)=10x-3

We move all terms to the left:

2x(4x+3)-(10x-3)=0

We multiply parentheses

8x^2+6x-(10x-3)=0

We get rid of parentheses

8x^2+6x-10x+3=0

We add all the numbers together, and all the variables

8x^2-4x+3=0

a = 8; b = -4; c = +3;
Δ = b2-4ac
Δ = -42-4·8·3
Δ = -80
Delta is less than zero, so there is no solution for the equation

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