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2x(4x+60)42=180
We move all terms to the left:
2x(4x+60)42-(180)=0
We multiply parentheses
336x^2+5040x-180=0
a = 336; b = 5040; c = -180;
Δ = b2-4ac
Δ = 50402-4·336·(-180)
Δ = 25643520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25643520}=\sqrt{2304*11130}=\sqrt{2304}*\sqrt{11130}=48\sqrt{11130}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5040)-48\sqrt{11130}}{2*336}=\frac{-5040-48\sqrt{11130}}{672} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5040)+48\sqrt{11130}}{2*336}=\frac{-5040+48\sqrt{11130}}{672} $
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