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2x(4x+7)-3(4x+7)=0
We multiply parentheses
8x^2+14x-12x-21=0
We add all the numbers together, and all the variables
8x^2+2x-21=0
a = 8; b = 2; c = -21;
Δ = b2-4ac
Δ = 22-4·8·(-21)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-26}{2*8}=\frac{-28}{16} =-1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+26}{2*8}=\frac{24}{16} =1+1/2 $
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