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2x(4x+7)-9(4x+7)=0
We multiply parentheses
8x^2+14x-36x-63=0
We add all the numbers together, and all the variables
8x^2-22x-63=0
a = 8; b = -22; c = -63;
Δ = b2-4ac
Δ = -222-4·8·(-63)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-50}{2*8}=\frac{-28}{16} =-1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+50}{2*8}=\frac{72}{16} =4+1/2 $
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