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2x(4x+7)=2x-4
We move all terms to the left:
2x(4x+7)-(2x-4)=0
We multiply parentheses
8x^2+14x-(2x-4)=0
We get rid of parentheses
8x^2+14x-2x+4=0
We add all the numbers together, and all the variables
8x^2+12x+4=0
a = 8; b = 12; c = +4;
Δ = b2-4ac
Δ = 122-4·8·4
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4}{2*8}=\frac{-16}{16} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4}{2*8}=\frac{-8}{16} =-1/2 $
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