2x(4x-3)=8x2-18

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Solution for 2x(4x-3)=8x2-18 equation:



2x(4x-3)=8x^2-18
We move all terms to the left:
2x(4x-3)-(8x^2-18)=0
We multiply parentheses
8x^2-6x-(8x^2-18)=0
We get rid of parentheses
8x^2-8x^2-6x+18=0
We add all the numbers together, and all the variables
-6x+18=0
We move all terms containing x to the left, all other terms to the right
-6x=-18
x=-18/-6
x=+3

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