2x(5+x)=17

Solution for 2x(5+x)=17 equation:

2x(5+x)=17

We move all terms to the left:

2x(5+x)-(17)=0

We add all the numbers together, and all the variables

2x(x+5)-17=0

We multiply parentheses

2x^2+10x-17=0

a = 2; b = 10; c = -17;
Δ = b2-4ac
Δ = 102-4·2·(-17)
Δ = 236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{236}=\sqrt{4*59}=\sqrt{4}*\sqrt{59}=2\sqrt{59}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{59}}{2*2}=\frac{-10-2\sqrt{59}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{59}}{2*2}=\frac{-10+2\sqrt{59}}{4}
$