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2x(5-4x)=2x(5-4x)
We move all terms to the left:
2x(5-4x)-(2x(5-4x))=0
We add all the numbers together, and all the variables
2x(-4x+5)-(2x(-4x+5))=0
We multiply parentheses
-8x^2+10x-(2x(-4x+5))=0
We calculate terms in parentheses: -(2x(-4x+5)), so:We get rid of parentheses
2x(-4x+5)
We multiply parentheses
-8x^2+10x
Back to the equation:
-(-8x^2+10x)
-8x^2+8x^2-10x+10x=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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