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2x(5x+3)=7x+24
We move all terms to the left:
2x(5x+3)-(7x+24)=0
We multiply parentheses
10x^2+6x-(7x+24)=0
We get rid of parentheses
10x^2+6x-7x-24=0
We add all the numbers together, and all the variables
10x^2-1x-24=0
a = 10; b = -1; c = -24;
Δ = b2-4ac
Δ = -12-4·10·(-24)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-31}{2*10}=\frac{-30}{20} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+31}{2*10}=\frac{32}{20} =1+3/5 $
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