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2x(6x+12)=288
We move all terms to the left:
2x(6x+12)-(288)=0
We multiply parentheses
12x^2+24x-288=0
a = 12; b = 24; c = -288;
Δ = b2-4ac
Δ = 242-4·12·(-288)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-120}{2*12}=\frac{-144}{24} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+120}{2*12}=\frac{96}{24} =4 $
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