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2x(x)+1+(x)=3(x-2)+7
We move all terms to the left:
2x(x)+1+(x)-(3(x-2)+7)=0
We add all the numbers together, and all the variables
x+2xx-(3(x-2)+7)+1=0
We calculate terms in parentheses: -(3(x-2)+7), so:We get rid of parentheses
3(x-2)+7
We multiply parentheses
3x-6+7
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
x+2xx-3x-1+1=0
We add all the numbers together, and all the variables
-2x+2xx=0
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