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2x(x+1)-1=2(x-1)
We move all terms to the left:
2x(x+1)-1-(2(x-1))=0
We multiply parentheses
2x^2+2x-(2(x-1))-1=0
We calculate terms in parentheses: -(2(x-1)), so:We get rid of parentheses
2(x-1)
We multiply parentheses
2x-2
Back to the equation:
-(2x-2)
2x^2+2x-2x+2-1=0
We add all the numbers together, and all the variables
2x^2+1=0
a = 2; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·2·1
Δ = -8
Delta is less than zero, so there is no solution for the equation
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