2x(x+1)-2=2(x-2)(x+3)

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Solution for 2x(x+1)-2=2(x-2)(x+3) equation: 



2x(x+1)-2=2(x-2)(x+3)

We move all terms to the left:

2x(x+1)-2-(2(x-2)(x+3))=0

We multiply parentheses

2x^2+2x-(2(x-2)(x+3))-2=0

We multiply parentheses ..

2x^2-(2(+x^2+3x-2x-6))+2x-2=0



We calculate terms in parentheses: -(2(+x^2+3x-2x-6)), so:

2(+x^2+3x-2x-6)

We multiply parentheses

2x^2+6x-4x-12

We add all the numbers together, and all the variables

2x^2+2x-12

Back to the equation:

-(2x^2+2x-12)



We add all the numbers together, and all the variables

2x^2+2x-(2x^2+2x-12)-2=0

We get rid of parentheses

2x^2-2x^2+2x-2x+12-2=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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