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2x(x+1)=220
We move all terms to the left:
2x(x+1)-(220)=0
We multiply parentheses
2x^2+2x-220=0
a = 2; b = 2; c = -220;
Δ = b2-4ac
Δ = 22-4·2·(-220)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-42}{2*2}=\frac{-44}{4} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+42}{2*2}=\frac{40}{4} =10 $
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