2x(x+10)=180

Solution for 2x(x+10)=180 equation:

2x(x+10)=180

We move all terms to the left:

2x(x+10)-(180)=0

We multiply parentheses

2x^2+20x-180=0

a = 2; b = 20; c = -180;
Δ = b2-4ac
Δ = 202-4·2·(-180)
Δ = 1840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1840}=\sqrt{16*115}=\sqrt{16}*\sqrt{115}=4\sqrt{115}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{115}}{2*2}=\frac{-20-4\sqrt{115}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{115}}{2*2}=\frac{-20+4\sqrt{115}}{4}
$