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2x(x+11)=-20
We move all terms to the left:
2x(x+11)-(-20)=0
We add all the numbers together, and all the variables
2x(x+11)+20=0
We multiply parentheses
2x^2+22x+20=0
a = 2; b = 22; c = +20;
Δ = b2-4ac
Δ = 222-4·2·20
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-18}{2*2}=\frac{-40}{4} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+18}{2*2}=\frac{-4}{4} =-1 $
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