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2x(x+16)=124
We move all terms to the left:
2x(x+16)-(124)=0
We multiply parentheses
2x^2+32x-124=0
a = 2; b = 32; c = -124;
Δ = b2-4ac
Δ = 322-4·2·(-124)
Δ = 2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2016}=\sqrt{144*14}=\sqrt{144}*\sqrt{14}=12\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-12\sqrt{14}}{2*2}=\frac{-32-12\sqrt{14}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+12\sqrt{14}}{2*2}=\frac{-32+12\sqrt{14}}{4} $
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