2x(x+2)+4x2-20x=3x(2x-6)+10

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Solution for 2x(x+2)+4x2-20x=3x(2x-6)+10 equation:



2x(x+2)+4x^2-20x=3x(2x-6)+10
We move all terms to the left:
2x(x+2)+4x^2-20x-(3x(2x-6)+10)=0
We add all the numbers together, and all the variables
4x^2-20x+2x(x+2)-(3x(2x-6)+10)=0
We multiply parentheses
4x^2+2x^2-20x+4x-(3x(2x-6)+10)=0
We calculate terms in parentheses: -(3x(2x-6)+10), so:
3x(2x-6)+10
We multiply parentheses
6x^2-18x+10
Back to the equation:
-(6x^2-18x+10)
We add all the numbers together, and all the variables
6x^2-16x-(6x^2-18x+10)=0
We get rid of parentheses
6x^2-6x^2-16x+18x-10=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5

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