2x(x+2)+x(x+2)=3(x+2)(x-2)

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Solution for 2x(x+2)+x(x+2)=3(x+2)(x-2) equation: 



2x(x+2)+x(x+2)=3(x+2)(x-2)

We move all terms to the left:

2x(x+2)+x(x+2)-(3(x+2)(x-2))=0

We use the square of the difference formula

x^2+2x(x+2)+x(x+2)+4=0

We multiply parentheses

x^2+2x^2+x^2+4x+2x+4=0

We add all the numbers together, and all the variables

4x^2+6x+4=0

a = 4; b = 6; c = +4;
Δ = b2-4ac
Δ = 62-4·4·4
Δ = -28
Delta is less than zero, so there is no solution for the equation

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