2x(x+2)=(3x-16)

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Solution for 2x(x+2)=(3x-16) equation: 



2x(x+2)=(3x-16)

We move all terms to the left:

2x(x+2)-((3x-16))=0

We multiply parentheses

2x^2+4x-((3x-16))=0



We calculate terms in parentheses: -((3x-16)), so:

(3x-16)

We get rid of parentheses

3x-16

Back to the equation:

-(3x-16)



We get rid of parentheses

2x^2+4x-3x+16=0

We add all the numbers together, and all the variables

2x^2+x+16=0

a = 2; b = 1; c = +16;
Δ = b2-4ac
Δ = 12-4·2·16
Δ = -127
Delta is less than zero, so there is no solution for the equation

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