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2x(x+27)=6x
We move all terms to the left:
2x(x+27)-(6x)=0
We add all the numbers together, and all the variables
-6x+2x(x+27)=0
We multiply parentheses
2x^2-6x+54x=0
We add all the numbers together, and all the variables
2x^2+48x=0
a = 2; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·2·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*2}=\frac{-96}{4} =-24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*2}=\frac{0}{4} =0 $
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