2x(x+3)-4(x-2)=2x+2

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Solution for 2x(x+3)-4(x-2)=2x+2 equation: 



2x(x+3)-4(x-2)=2x+2

We move all terms to the left:

2x(x+3)-4(x-2)-(2x+2)=0

We multiply parentheses

2x^2+6x-4x-(2x+2)+8=0

We get rid of parentheses

2x^2+6x-4x-2x-2+8=0

We add all the numbers together, and all the variables

2x^2+6=0

a = 2; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·2·6
Δ = -48
Delta is less than zero, so there is no solution for the equation

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