2x(x+3)=(x-1)(2x-5)

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Solution for 2x(x+3)=(x-1)(2x-5) equation: 



2x(x+3)=(x-1)(2x-5)

We move all terms to the left:

2x(x+3)-((x-1)(2x-5))=0

We multiply parentheses

2x^2+6x-((x-1)(2x-5))=0

We multiply parentheses ..

2x^2-((+2x^2-5x-2x+5))+6x=0



We calculate terms in parentheses: -((+2x^2-5x-2x+5)), so:

(+2x^2-5x-2x+5)

We get rid of parentheses

2x^2-5x-2x+5

We add all the numbers together, and all the variables

2x^2-7x+5

Back to the equation:

-(2x^2-7x+5)



We add all the numbers together, and all the variables

2x^2+6x-(2x^2-7x+5)=0

We get rid of parentheses

2x^2-2x^2+6x+7x-5=0

We add all the numbers together, and all the variables

13x-5=0

We move all terms containing x to the left, all other terms to the right

13x=5

x=5/13

x=5/13

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