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2x(x+3)=2*2x+15
We move all terms to the left:
2x(x+3)-(2*2x+15)=0
We multiply parentheses
2x^2+6x-(2*2x+15)=0
We get rid of parentheses
2x^2+6x-2*2x-15=0
Wy multiply elements
2x^2+6x-4x-15=0
We add all the numbers together, and all the variables
2x^2+2x-15=0
a = 2; b = 2; c = -15;
Δ = b2-4ac
Δ = 22-4·2·(-15)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{31}}{2*2}=\frac{-2-2\sqrt{31}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{31}}{2*2}=\frac{-2+2\sqrt{31}}{4} $
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