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2x(x+3)=3(x-3)
We move all terms to the left:
2x(x+3)-(3(x-3))=0
We multiply parentheses
2x^2+6x-(3(x-3))=0
We calculate terms in parentheses: -(3(x-3)), so:We get rid of parentheses
3(x-3)
We multiply parentheses
3x-9
Back to the equation:
-(3x-9)
2x^2+6x-3x+9=0
We add all the numbers together, and all the variables
2x^2+3x+9=0
a = 2; b = 3; c = +9;
Δ = b2-4ac
Δ = 32-4·2·9
Δ = -63
Delta is less than zero, so there is no solution for the equation
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