2x(x+3)=6x-x2

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Solution for 2x(x+3)=6x-x2 equation: 



2x(x+3)=6x-x2

We move all terms to the left:

2x(x+3)-(6x-x2)=0

We add all the numbers together, and all the variables

-(+6x-1x^2)+2x(x+3)=0

We multiply parentheses

-(+6x-1x^2)+2x^2+6x=0

We get rid of parentheses

1x^2+2x^2-6x+6x=0

We add all the numbers together, and all the variables

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$

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