2x(x+3)=98

Solution for 2x(x+3)=98 equation:

2x(x+3)=98

We move all terms to the left:

2x(x+3)-(98)=0

We multiply parentheses

2x^2+6x-98=0

a = 2; b = 6; c = -98;
Δ = b2-4ac
Δ = 62-4·2·(-98)
Δ = 820
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{820}=\sqrt{4*205}=\sqrt{4}*\sqrt{205}=2\sqrt{205}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{205}}{2*2}=\frac{-6-2\sqrt{205}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{205}}{2*2}=\frac{-6+2\sqrt{205}}{4}
$