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2x(x+30)-(x-10)=0
We multiply parentheses
2x^2+60x-(x-10)=0
We get rid of parentheses
2x^2+60x-x+10=0
We add all the numbers together, and all the variables
2x^2+59x+10=0
a = 2; b = 59; c = +10;
Δ = b2-4ac
Δ = 592-4·2·10
Δ = 3401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-\sqrt{3401}}{2*2}=\frac{-59-\sqrt{3401}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+\sqrt{3401}}{2*2}=\frac{-59+\sqrt{3401}}{4} $
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