2x(x+30)=64

Solution for 2x(x+30)=64 equation:

2x(x+30)=64

We move all terms to the left:

2x(x+30)-(64)=0

We multiply parentheses

2x^2+60x-64=0

a = 2; b = 60; c = -64;
Δ = b2-4ac
Δ = 602-4·2·(-64)
Δ = 4112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4112}=\sqrt{16*257}=\sqrt{16}*\sqrt{257}=4\sqrt{257}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{257}}{2*2}=\frac{-60-4\sqrt{257}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{257}}{2*2}=\frac{-60+4\sqrt{257}}{4}
$