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2x(x+4)-4x=3(x-1)
We move all terms to the left:
2x(x+4)-4x-(3(x-1))=0
We add all the numbers together, and all the variables
-4x+2x(x+4)-(3(x-1))=0
We multiply parentheses
2x^2-4x+8x-(3(x-1))=0
We calculate terms in parentheses: -(3(x-1)), so:We add all the numbers together, and all the variables
3(x-1)
We multiply parentheses
3x-3
Back to the equation:
-(3x-3)
2x^2+4x-(3x-3)=0
We get rid of parentheses
2x^2+4x-3x+3=0
We add all the numbers together, and all the variables
2x^2+x+3=0
a = 2; b = 1; c = +3;
Δ = b2-4ac
Δ = 12-4·2·3
Δ = -23
Delta is less than zero, so there is no solution for the equation
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