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2x(x+4)-5=3x-10
We move all terms to the left:
2x(x+4)-5-(3x-10)=0
We multiply parentheses
2x^2+8x-(3x-10)-5=0
We get rid of parentheses
2x^2+8x-3x+10-5=0
We add all the numbers together, and all the variables
2x^2+5x+5=0
a = 2; b = 5; c = +5;
Δ = b2-4ac
Δ = 52-4·2·5
Δ = -15
Delta is less than zero, so there is no solution for the equation
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