2x(x+4)=110

Solution for 2x(x+4)=110 equation:

2x(x+4)=110

We move all terms to the left:

2x(x+4)-(110)=0

We multiply parentheses

2x^2+8x-110=0

a = 2; b = 8; c = -110;
Δ = b2-4ac
Δ = 82-4·2·(-110)
Δ = 944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{944}=\sqrt{16*59}=\sqrt{16}*\sqrt{59}=4\sqrt{59}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{59}}{2*2}=\frac{-8-4\sqrt{59}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{59}}{2*2}=\frac{-8+4\sqrt{59}}{4}
$