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2x(x+4)=64
We move all terms to the left:
2x(x+4)-(64)=0
We multiply parentheses
2x^2+8x-64=0
a = 2; b = 8; c = -64;
Δ = b2-4ac
Δ = 82-4·2·(-64)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24}{2*2}=\frac{-32}{4} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24}{2*2}=\frac{16}{4} =4 $
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