2x(x+5)+3/5x+2=x(2x+3)-x2

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Solution for 2x(x+5)+3/5x+2=x(2x+3)-x2 equation: 



2x(x+5)+3/5x+2=x(2x+3)-x2

We move all terms to the left:

2x(x+5)+3/5x+2-(x(2x+3)-x2)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We multiply parentheses

2x^2+10x+3/5x-(x(2x+3)-x2)+2=0

We multiply all the terms by the denominator


2x^2*5x+10x*5x-((x(2x+3)-x2))*5x+2*5x+3=0

Wy multiply elements

10x^3+50x^2-((x(2x+3)-x2))*5x+10x+3=0

We do not support expression: x^3

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