2x(x+5)-4x=6x+242

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Solution for 2x(x+5)-4x=6x+242 equation:



2x(x+5)-4x=6x+242
We move all terms to the left:
2x(x+5)-4x-(6x+242)=0
We add all the numbers together, and all the variables
-4x+2x(x+5)-(6x+242)=0
We multiply parentheses
2x^2-4x+10x-(6x+242)=0
We get rid of parentheses
2x^2-4x+10x-6x-242=0
We add all the numbers together, and all the variables
2x^2-242=0
a = 2; b = 0; c = -242;
Δ = b2-4ac
Δ = 02-4·2·(-242)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-44}{2*2}=\frac{-44}{4} =-11 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+44}{2*2}=\frac{44}{4} =11 $

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