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2x(x+5)=-21-9x
We move all terms to the left:
2x(x+5)-(-21-9x)=0
We add all the numbers together, and all the variables
2x(x+5)-(-9x-21)=0
We multiply parentheses
2x^2+10x-(-9x-21)=0
We get rid of parentheses
2x^2+10x+9x+21=0
We add all the numbers together, and all the variables
2x^2+19x+21=0
a = 2; b = 19; c = +21;
Δ = b2-4ac
Δ = 192-4·2·21
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{193}}{2*2}=\frac{-19-\sqrt{193}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{193}}{2*2}=\frac{-19+\sqrt{193}}{4} $
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