2x(x+5)=-x(10-2x)+100

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Solution for 2x(x+5)=-x(10-2x)+100 equation: 



2x(x+5)=-x(10-2x)+100

We move all terms to the left:

2x(x+5)-(-x(10-2x)+100)=0

We add all the numbers together, and all the variables

2x(x+5)-(-x(-2x+10)+100)=0

We multiply parentheses

2x^2+10x-(-x(-2x+10)+100)=0



We calculate terms in parentheses: -(-x(-2x+10)+100), so:

-x(-2x+10)+100

We multiply parentheses

2x^2-10x+100

Back to the equation:

-(2x^2-10x+100)



We get rid of parentheses

2x^2-2x^2+10x+10x-100=0

We add all the numbers together, and all the variables

20x-100=0

We move all terms containing x to the left, all other terms to the right

20x=100

x=100/20

x=5

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