2x(x+5)=44

Solution for 2x(x+5)=44 equation:

2x(x+5)=44

We move all terms to the left:

2x(x+5)-(44)=0

We multiply parentheses

2x^2+10x-44=0

a = 2; b = 10; c = -44;
Δ = b2-4ac
Δ = 102-4·2·(-44)
Δ = 452
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{452}=\sqrt{4*113}=\sqrt{4}*\sqrt{113}=2\sqrt{113}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{113}}{2*2}=\frac{-10-2\sqrt{113}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{113}}{2*2}=\frac{-10+2\sqrt{113}}{4}
$