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2x(x+5)=75x+x2
We move all terms to the left:
2x(x+5)-(75x+x2)=0
We add all the numbers together, and all the variables
-(+75x+x^2)+2x(x+5)=0
We multiply parentheses
-(+75x+x^2)+2x^2+10x=0
We get rid of parentheses
-x^2+2x^2-75x+10x=0
We add all the numbers together, and all the variables
x^2-65x=0
a = 1; b = -65; c = 0;
Δ = b2-4ac
Δ = -652-4·1·0
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-65}{2*1}=\frac{0}{2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+65}{2*1}=\frac{130}{2} =65 $
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