2x(x+5)=83

Solution for 2x(x+5)=83 equation:

2x(x+5)=83

We move all terms to the left:

2x(x+5)-(83)=0

We multiply parentheses

2x^2+10x-83=0

a = 2; b = 10; c = -83;
Δ = b2-4ac
Δ = 102-4·2·(-83)
Δ = 764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{764}=\sqrt{4*191}=\sqrt{4}*\sqrt{191}=2\sqrt{191}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{191}}{2*2}=\frac{-10-2\sqrt{191}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{191}}{2*2}=\frac{-10+2\sqrt{191}}{4}
$