2x(x+6)=(x+4)(x-4)(x+3)

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Solution for 2x(x+6)=(x+4)(x-4)(x+3) equation: 


Simplifying
2x(x + 6) = (x + 4)(x + -4)(x + 3)

Reorder the terms:
2x(6 + x) = (x + 4)(x + -4)(x + 3)
(6 * 2x + x * 2x) = (x + 4)(x + -4)(x + 3)
(12x + 2x2) = (x + 4)(x + -4)(x + 3)

Reorder the terms:
12x + 2x2 = (4 + x)(x + -4)(x + 3)

Reorder the terms:
12x + 2x2 = (4 + x)(-4 + x)(x + 3)

Reorder the terms:
12x + 2x2 = (4 + x)(-4 + x)(3 + x)

Multiply (4 + x) * (-4 + x)
12x + 2x2 = (4(-4 + x) + x(-4 + x))(3 + x)
12x + 2x2 = ((-4 * 4 + x * 4) + x(-4 + x))(3 + x)
12x + 2x2 = ((-16 + 4x) + x(-4 + x))(3 + x)
12x + 2x2 = (-16 + 4x + (-4 * x + x * x))(3 + x)
12x + 2x2 = (-16 + 4x + (-4x + x2))(3 + x)

Combine like terms: 4x + -4x = 0
12x + 2x2 = (-16 + 0 + x2)(3 + x)
12x + 2x2 = (-16 + x2)(3 + x)

Multiply (-16 + x2) * (3 + x)
12x + 2x2 = (-16(3 + x) + x2(3 + x))
12x + 2x2 = ((3 * -16 + x * -16) + x2(3 + x))
12x + 2x2 = ((-48 + -16x) + x2(3 + x))
12x + 2x2 = (-48 + -16x + (3 * x2 + x * x2))
12x + 2x2 = (-48 + -16x + (3x2 + x3))
12x + 2x2 = (-48 + -16x + 3x2 + x3)

Solving
12x + 2x2 = -48 + -16x + 3x2 + x3

Solving for variable 'x'.

Reorder the terms:
48 + 12x + 16x + 2x2 + -3x2 + -1x3 = -48 + -16x + 3x2 + x3 + 48 + 16x + -3x2 + -1x3

Combine like terms: 12x + 16x = 28x
48 + 28x + 2x2 + -3x2 + -1x3 = -48 + -16x + 3x2 + x3 + 48 + 16x + -3x2 + -1x3

Combine like terms: 2x2 + -3x2 = -1x2
48 + 28x + -1x2 + -1x3 = -48 + -16x + 3x2 + x3 + 48 + 16x + -3x2 + -1x3

Reorder the terms:
48 + 28x + -1x2 + -1x3 = -48 + 48 + -16x + 16x + 3x2 + -3x2 + x3 + -1x3

Combine like terms: -48 + 48 = 0
48 + 28x + -1x2 + -1x3 = 0 + -16x + 16x + 3x2 + -3x2 + x3 + -1x3
48 + 28x + -1x2 + -1x3 = -16x + 16x + 3x2 + -3x2 + x3 + -1x3

Combine like terms: -16x + 16x = 0
48 + 28x + -1x2 + -1x3 = 0 + 3x2 + -3x2 + x3 + -1x3
48 + 28x + -1x2 + -1x3 = 3x2 + -3x2 + x3 + -1x3

Combine like terms: 3x2 + -3x2 = 0
48 + 28x + -1x2 + -1x3 = 0 + x3 + -1x3
48 + 28x + -1x2 + -1x3 = x3 + -1x3

Combine like terms: x3 + -1x3 = 0
48 + 28x + -1x2 + -1x3 = 0

The solution to this equation could not be determined.

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