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2x(x+6)=520
We move all terms to the left:
2x(x+6)-(520)=0
We multiply parentheses
2x^2+12x-520=0
a = 2; b = 12; c = -520;
Δ = b2-4ac
Δ = 122-4·2·(-520)
Δ = 4304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4304}=\sqrt{16*269}=\sqrt{16}*\sqrt{269}=4\sqrt{269}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{269}}{2*2}=\frac{-12-4\sqrt{269}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{269}}{2*2}=\frac{-12+4\sqrt{269}}{4} $
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