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2x(x+9)+60=180
We move all terms to the left:
2x(x+9)+60-(180)=0
We add all the numbers together, and all the variables
2x(x+9)-120=0
We multiply parentheses
2x^2+18x-120=0
a = 2; b = 18; c = -120;
Δ = b2-4ac
Δ = 182-4·2·(-120)
Δ = 1284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1284}=\sqrt{4*321}=\sqrt{4}*\sqrt{321}=2\sqrt{321}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{321}}{2*2}=\frac{-18-2\sqrt{321}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{321}}{2*2}=\frac{-18+2\sqrt{321}}{4} $
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