2x(x-1)+8=4x-20

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Solution for 2x(x-1)+8=4x-20 equation: 



2x(x-1)+8=4x-20

We move all terms to the left:

2x(x-1)+8-(4x-20)=0

We multiply parentheses

2x^2-2x-(4x-20)+8=0

We get rid of parentheses

2x^2-2x-4x+20+8=0

We add all the numbers together, and all the variables

2x^2-6x+28=0

a = 2; b = -6; c = +28;
Δ = b2-4ac
Δ = -62-4·2·28
Δ = -188
Delta is less than zero, so there is no solution for the equation

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