2x(x-1)=7x2-3x

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Solution for 2x(x-1)=7x2-3x equation:



2x(x-1)=7x^2-3x
We move all terms to the left:
2x(x-1)-(7x^2-3x)=0
We multiply parentheses
2x^2-2x-(7x^2-3x)=0
We get rid of parentheses
2x^2-7x^2-2x+3x=0
We add all the numbers together, and all the variables
-5x^2+x=0
a = -5; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-5)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-5}=\frac{-2}{-10} =1/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-5}=\frac{0}{-10} =0 $

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