2x(x-2)=x(2x+4)+32

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Solution for 2x(x-2)=x(2x+4)+32 equation: 



2x(x-2)=x(2x+4)+32

We move all terms to the left:

2x(x-2)-(x(2x+4)+32)=0

We multiply parentheses

2x^2-4x-(x(2x+4)+32)=0



We calculate terms in parentheses: -(x(2x+4)+32), so:

x(2x+4)+32

We multiply parentheses

2x^2+4x+32

Back to the equation:

-(2x^2+4x+32)



We get rid of parentheses

2x^2-2x^2-4x-4x-32=0

We add all the numbers together, and all the variables

-8x-32=0

We move all terms containing x to the left, all other terms to the right

-8x=32

x=32/-8

x=-4

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